Let’s list all possible places where subqueries in MySQL or Hive QL or Pyspark SQL Query can be used:
1. In the SELECT Clause
Subqueries can compute a value for each row.
SELECT employee_id,
(SELECT COUNT(*) FROM project_assignments pa WHERE pa.employee_id = e.employee_id) AS project_count
FROM employees e;
2. In the FROM Clause
Subqueries can be used as derived tables.
SELECT e.employee_id, e.name, pa.project_count
FROM employees e
JOIN (SELECT employee_id, COUNT(DISTINCT project_id) AS project_count
FROM project_assignments
GROUP BY employee_id) pa
ON e.employee_id = pa.employee_id;
3. In the WHERE Clause
Subqueries can filter rows based on conditions.
SELECT employee_id, name
FROM employees
WHERE department_id = (SELECT department_id FROM departments WHERE department_name = 'Sales');
4. In the HAVING
Clause
Subqueries can filter groups of rows.
SELECT e.employee_id, e.name
FROM employees e
JOIN project_assignments pa ON e.employee_id = pa.employee_id
GROUP BY e.employee_id, e.name
HAVING COUNT(DISTINCT pa.project_id) = (SELECT COUNT(DISTINCT project_id) FROM projects);
5. In the INSERT
Statement
Subqueries can insert data based on a query.
INSERT INTO employees_archive (employee_id, name)
SELECT employee_id, name
FROM employees
WHERE hire_date < '2000-01-01';
6. In the UPDATE
Statement
Subqueries can update records based on a query.
UPDATE employees
SET department_id = (SELECT department_id FROM departments WHERE department_name = 'Sales')
WHERE employee_id = 123;
7. In the DELETE
Statement
Subqueries can delete records based on a query.
DELETE FROM employees
WHERE employee_id IN (SELECT employee_id FROM employees WHERE hire_date < '2000-01-01');
8. In the EXISTS
Condition
Subqueries can test for the existence of rows.
SELECT employee_id, name
FROM employees e
WHERE EXISTS (SELECT 1 FROM project_assignments pa WHERE pa.employee_id = e.employee_id);
9. In the WITH
Clause (Common Table Expressions)
Subqueries can define temporary result sets.
WITH project_counts AS (
SELECT employee_id, COUNT(DISTINCT project_id) AS project_count
FROM project_assignments
GROUP BY employee_id
)
SELECT e.employee_id, e.name
FROM employees e
JOIN project_counts pc ON e.employee_id = pc.employee_id
WHERE pc.project_count = (SELECT COUNT(DISTINCT project_id) FROM projects);
10. In the CASE
Statement
Subqueries can be used within CASE
statements.
SELECT employee_id,
name,
CASE
WHEN (SELECT COUNT(*) FROM project_assignments pa WHERE pa.employee_id = e.employee_id) > 5 THEN 'Senior'
ELSE 'Junior'
END AS position
FROM employees e;
11. In the ORDER BY
Clause
Subqueries can be used to determine the order of rows.
SELECT employee_id, name
FROM employees
ORDER BY (SELECT COUNT(*) FROM project_assignments pa WHERE pa.employee_id = employees.employee_id) DESC;
12. In the JOIN
Condition
Subqueries can be part of the join condition.
SELECT e.employee_id, e.name
FROM employees e
JOIN departments d ON e.department_id = d.department_id
AND e.salary > (SELECT AVG(salary) FROM employees WHERE department_id = d.department_id);
13. In the UNION
or UNION ALL
Clause
Subqueries can be used in union operations.
SELECT employee_id, name
FROM employees
WHERE department_id = (SELECT department_id FROM departments WHERE department_name = 'Sales')
UNION
SELECT employee_id, name
FROM employees
WHERE department_id = (SELECT department_id FROM departments WHERE department_name = 'HR');
By recognizing all these potential placements of subqueries, you can leverage them to build highly sophisticated and efficient SQL queries.
can we use it in group by
Subqueries are generally not used directly within the GROUP BY
clause. The GROUP BY
clause is used to group rows that have the same values in specified columns into aggregated data. However, subqueries can be used in conjunction with GROUP BY
in other parts of the query, such as the SELECT
, HAVING
, and FROM
clauses, as demonstrated earlier.
Here’s an example to clarify how subqueries can work around GROUP BY
:
Using Subqueries with GROUP BY
:
Example Scenario:
Suppose you have an employees
table and a project_assignments
table. You want to find employees who have worked on all projects for a given year.
Step-by-Step Example:
- Create the necessary tables and insert sample data:
CREATE TABLE employees (
employee_id INT PRIMARY KEY,
name VARCHAR(100)
);
CREATE TABLE projects (
project_id INT PRIMARY KEY,
project_name VARCHAR(100),
project_year INT
);
CREATE TABLE project_assignments (
employee_id INT,
project_id INT,
FOREIGN KEY (employee_id) REFERENCES employees(employee_id),
FOREIGN KEY (project_id) REFERENCES projects(project_id)
);
INSERT INTO employees (employee_id, name) VALUES (1, 'Alice'), (2, 'Bob'), (3, 'Charlie');
INSERT INTO projects (project_id, project_name, project_year) VALUES (1, 'ProjectA', 2023), (2, 'ProjectB', 2023), (3, 'ProjectC', 2023);
INSERT INTO project_assignments (employee_id, project_id) VALUES (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1);
- Use a subquery with
GROUP BY
to find employees who worked on all projects for the year 2023:
SELECT e.employee_id, e.name
FROM employees e
JOIN (
SELECT employee_id
FROM project_assignments pa
JOIN projects p ON pa.project_id = p.project_id
WHERE p.project_year = 2023
GROUP BY employee_id
HAVING COUNT(DISTINCT pa.project_id) = (SELECT COUNT(DISTINCT project_id) FROM projects WHERE project_year = 2023)
) all_projects ON e.employee_id = all_projects.employee_id;
- The inner subquery (
all_projects
) selectsemployee_id
s from theproject_assignments
table, joined with theprojects
table to filter by the year 2023. - The subquery groups by
employee_id
and uses theHAVING
clause to check if the count of distinct project IDs for each employee matches the total number of distinct projects for 2023. - The outer query joins the
employees
table with the subquery to get the names of employees who have worked on all projects for the year 2023.
In this example, the subquery is not directly in the GROUP BY
clause but works in conjunction with it to achieve the desired results. This illustrates how subqueries can be used effectively with GROUP BY
to create complex queries.
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