There is a simple way-
You can use the calendar module in Python to create a calendar for the current year. But it defeats the purpose – of getting your hands dirty by writing big lengthy Python Code. But anyway i am adding it here:-

You can use the calendar module in Python to create a calendar for the current year. Here’s a simple Python program to achieve that.

import calendar

def create_calendar(year):
    # Create a TextCalendar instance
    cal = calendar.TextCalendar(calendar.SUNDAY)  # Start week on Sunday

    # Generate the calendar for the given year
    calendar_text = cal.formatyear(year, 2, 1, 1, 3) 
 # 2 spaces between months, 1 row between months, 1 column between months, 3 months per row

    return calendar_text

def main():
    # Get the current year
    current_year = calendar.datetime.datetime.now().year

    # Create calendar for the current year
    calendar_text = create_calendar(current_year)

    # Display the calendar
    print(f"Calendar for the year {current_year}:n")
    print(calendar_text)

if __name__ == "__main__":
    main()

This program creates a calendar for the current year using the TextCalendar class from the calendar module. It then formats the calendar as text and prints it to the console. The calendar starts the week on Sunday and formats the months with 2 spaces between them, 1 row between them, 1 column between them, and displays 3 months per row. You can adjust these parameters based on your preferences.

Creating a calendar without importing the calendar package involves implementing the logic for generating the calendar manually. Here’s a Python program that generates a calendar for the current year without using the calendar package:

import datetime

def is_leap_year(year):
    """Check if a year is a leap year."""
    if year % 4 == 0 and (year % 100 != 0 or year % 400 == 0):
        return True
    return False

def get_month_days(year, month):
    """Get the number of days in a month."""
    if month in {1, 3, 5, 7, 8, 10, 12}:
        return 31
    elif month in {4, 6, 9, 11}:
        return 30
    elif is_leap_year(year):
        return 29
    else:
        return 28

def create_calendar(year):
    """Create a calendar for the given year."""
    months = ["January", "February", "March", "April", "May", "June",
              "July", "August", "September", "October", "November", "December"]

    calendar_text = ""

    for month_num, month_name in enumerate(months, start=1):
        calendar_text += f"n{month_name}n"
        calendar_text += "Mo Tu We Th Fr Sa Sun"

        # Get the first day of the month
        first_day = datetime.date(year, month_num, 1).weekday()

        # Fill the leading spaces
        calendar_text += "   " * first_day

        # Fill in the days of the month
        for day in range(1, get_month_days(year, month_num) + 1):
            calendar_text += f"{day:2d} "
            first_day += 1
            if first_day == 7:
                calendar_text += "n"
                first_day = 0
        calendar_text += "n"

    return calendar_text

def main():
    # Get the current year
    current_year = datetime.datetime.now().year

    # Create calendar for the current year
    calendar_text = create_calendar(current_year)

    # Display the calendar
    print(f"Calendar for the year {current_year}:n")
    print(calendar_text)

if __name__ == "__main__":
    main()

This program calculates the days of the week and fills in the dates for each month manually. It also accounts for leap years to determine the number of days in February. The generated calendar is printed to the console for the current year.